课评: 转出学生归档(王子墨/张立坤/黄俊博)+ 周四班级总结 + 新生章梓皓档案 + C++示例代码

This commit is contained in:
chengzi
2026-09-29 22:43:54 +08:00
parent 6f57dfe67e
commit 73cce4c4f5
116 changed files with 6817 additions and 248 deletions

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"6602": {
"title": "简单排序 - 选择题 - 题目详情 - 穹狼科创",
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{
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"text": "【202503】对数组 arr[]={5, 3, 8, 1} 进行升序排序,执行第一轮冒泡排序后数组 arr 中的内容为( )。",
"options": [
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"3, 1, 5, 8",
"3, 5, 8, 1",
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},
{
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"text": "【202506】小杨在整理一副扑克牌的所有红心扑克牌,使其从小到大排列。他的做法是:最开始抓到第1张扑克牌被认为已经排好序;然后抓第2张扑克牌,将其插入至有序部分的正确位置;不断循环步骤,每次将新抓到扑克牌插入至有序部分,直至抓完所有扑克牌,这样抓牌结束时就完成了扑克牌的排序。小杨这种整理扑克牌的方式与( )排序的方式最接近。",
"options": [
"冒泡排序",
"插入排序",
"选择排序",
"直接排序"
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{
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"text": "【202509】关于排序算法的稳定性,以下说法错误的是( )。",
"options": [
"稳定的排序算法不改变相等元素的相对位置",
"冒泡排序是稳定的排序算法",
"选择排序是稳定的排序算法",
"插入排序是稳定的排序算法"
]
},
{
"no": 4,
"text": "【202606】下面代码使用某种排序算法,将数组中的元素按从小到大排序。这段代码使用的排序算法是( )。 void mystery_sort(double arr[], int n) { for (int i = 0; i < n - 1; i++) { int minPos = i; for (int j = i + 1; j < n; j++) { if (arr[j] < arr[minPos]) { minPos = j; } } double temp = arr[i]; arr[i] = arr[minPos]; arr[minPos] = temp; } }",
"options": [
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"插入排序",
"选择排序",
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]
},
{
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"text": "【202509】关于插入排序的时间复杂度,下列说法正确的是( )。",
"options": [
"最好情况和最坏情况的时间复杂度都是",
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"title": "简单排序 - 判断题 - 题目详情 - 穹狼科创",
"questions": [
{
"no": 1,
"text": "【202509】对整数数组 {4, 1, 3, 1, 5, 2} 进行冒泡排序(将最大元素放到最后),执行一轮之后是 {4, 1, 3, 1, 2, 5} 。",
"options": [
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"错误"
]
},
{
"no": 2,
"text": "【202503】对数组 arr[]={4, 3, 1, 5, 2} 进行升序排序,执行第一轮选择排序后数组arr中的内容是 {1, 4, 3, 5, 2} 。",
"options": [
"正确",
"错误"
]
},
{
"no": 3,
"text": "【202512】冒泡排序和插入排序都是稳定排序算法。",
"options": [
"正确",
"错误"
]
},
{
"no": 4,
"text": "【202606】如果使用带 flag 的冒泡排序,且待排序数组一开始就是有序的,那么算法只需一轮扫描即可结束,时间复杂度为 O ( n ) 。",
"options": [
"正确",
"错误"
]
},
{
"no": 5,
"text": "【202603】由于选择排序和插入排序的时间复杂度均为 O ( n 2 ) ,在任何实际场景下两者的性能表现几乎相同,可以互相替代。( )",
"options": [
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"错误"
]
}
]
}
}
}

View File

@@ -0,0 +1,342 @@
{
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"rid": "6aa4fcd225d632ee5c41d61e",
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"rid": "6aa4ffd425d632ee5c41dd5c",
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View File

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"text": "【202509】对整数数组 {4, 1, 3, 1, 5, 2} 进行冒泡排序(将最大元素放到最后),执行一轮之后是 {4, 1, 3, 1, 2, 5} 。",
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},
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},
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"错误"
]
},
{
"no": 4,
"text": "【202606】如果使用带 flag 的冒泡排序,且待排序数组一开始就是有序的,那么算法只需一轮扫描即可结束,时间复杂度为 O ( n ) 。",
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"错误"
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},
{
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}