1423 lines
43 KiB
JSON
1423 lines
43 KiB
JSON
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|
||
},
|
||
{
|
||
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|
||
"pid": 4410,
|
||
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|
||
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|
||
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|
||
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||
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||
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|
||
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|
||
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|
||
}
|
||
]
|
||
},
|
||
{
|
||
"tid": "tid1",
|
||
"pid": 4413,
|
||
"title": "每列最大值",
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||
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|
||
}
|
||
]
|
||
},
|
||
{
|
||
"tid": "tid1",
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||
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||
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||
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||
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||
},
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||
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||
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||
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||
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||
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||
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|
||
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||
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||
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||
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||
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|
||
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|
||
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||
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|
||
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||
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||
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||
}
|
||
]
|
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},
|
||
{
|
||
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||
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|
||
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||
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|
||
}
|
||
]
|
||
},
|
||
{
|
||
"tid": "tid2",
|
||
"pid": 4411,
|
||
"title": "矩阵元素总和",
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||
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||
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||
"code": "#include<bits/stdc++.h>\nusing namespace std;\nint l[2500][2500];\n\nint main(){\n int n,m,sum = 0;\n cin >> n >> m;\n for(int i = 1;i <= n;i++){\n \tfor(int j = 1;j <= m;j++){\n \t\tcin >> l[i][j];\n\t\t}\n\t}\n for(int j = 1;j <= m;j++){\n \tfor(int i = 1;i <= n;i++){\t\t\n\t\tsum += l[i][j];\n\t }\n\t}cout << sum;\n\treturn 0;\n}"
|
||
}
|
||
]
|
||
}
|
||
]
|
||
},
|
||
{
|
||
"uid": 369,
|
||
"name": "汪子杰",
|
||
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|
||
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|
||
],
|
||
"stats": {
|
||
"assigned": 17,
|
||
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||
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||
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||
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|
||
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||
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||
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|
||
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|
||
},
|
||
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|
||
{
|
||
"tid": "tid1",
|
||
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|
||
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||
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|
||
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|
||
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||
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||
"code": "#include<bits/stdc++.h>\nusing namespace std;\nint a[110][110];\nint main(){\n\tint n,m,num,cnt=0;\n\tcin>>n>>m;\n\tfor(int i=1;i<=n;i++){\n\t\tfor(int j=1;j<=m;j++){\n\t\t\tcin>>a[i][j];\n\t\t}\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tfor(int j=1;j<=m;j++){\n\t\t\tcin>>num;\n\t\t\tif(num==a[i][j]){\n\t\t\t\tcnt++;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<fixed<<setprecision(2)<<100.0*cnt/(n*m);\n\treturn 0;\n} "
|
||
}
|
||
]
|
||
},
|
||
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|
||
"tid": "tid1",
|
||
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|
||
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|
||
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|
||
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|
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||
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||
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|
||
}
|
||
]
|
||
},
|
||
{
|
||
"tid": "tid1",
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||
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|
||
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||
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|
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||
}
|
||
]
|
||
},
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||
{
|
||
"tid": "tid1",
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||
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||
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||
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||
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|
||
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||
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||
},
|
||
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|
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|
||
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||
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||
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|
||
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|
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|
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||
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|
||
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},
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|
||
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||
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||
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},
|
||
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|
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||
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|
||
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||
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||
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||
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||
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||
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||
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||
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||
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|
||
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|
||
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||
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|
||
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||
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|
||
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||
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||
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||
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|
||
},
|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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||
"code": "#include <bits/stdc++.h>\nusing namespace std;\nint arr[110][110];\nint main(){\n\tint n,m,num,cnt=0;\n\tcin>>n>>m; \n\tfor(int i=1; i<=n;i++){\n\t\tfor(int j=1; j<=m;j++){\n\t\tcin>>arr[i][j];\n\t\t}\n\t}\n\tfor(int i=1; i<=n;i++){\n\t\tfor(int j=1; j<=m;j++){\n\t\t\tcin>>num;\n\t\t\tif(num==arr[i][j]){\n\t\t\t\tcnt++;\n\t\t\t}\t\n\t\t}\n\tcout<<fixed<<setprecision(2)<<100.0*cnt/(n*m);\n\t}\n return 0;\n}"
|
||
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|
||
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|
||
},
|
||
{
|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
}
|
||
]
|
||
},
|
||
{
|
||
"tid": "tid1",
|
||
"pid": 4406,
|
||
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|
||
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|
||
{
|
||
"seq": 1,
|
||
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||
"score": 0,
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||
"rid": "6ab71897713ff6370c5ab601",
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||
"lang": "cc.cc14o2",
|
||
"errorHead": "foo.cc:16:10: error: expected '}' at end of input",
|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
||
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|
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|
||
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|
||
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|
||
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||
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|
||
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|
||
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|
||
"code": "#include <iostream>\nusing namespace std;\n\nconst int N = 55;\nint a[N][N], b[N][N];\n\nint main(){\n int n, m;\n cin >> n >> m;\n for(int i = 0; i < n; i++){\n for(int j = 0; j < m; j++){\n cin >> a[i][j];\n }\n }\n for(int i = 0; i < n; i++){\n for(int j = 0; j < m; j++){\n cin >> b[i][j];\n }\n }\n for(int i = 0; i < n; i++){\n for(int j = 0; j < m; j++){\n if(j > 0) cout << \" \";\n cout << a[i][j] + b[i][j];\n }\n cout << endl;\n }\n return 0;\n}"
|
||
}
|
||
]
|
||
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|
||
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|
||
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|
||
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|
||
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"code": "#include <stdio.h>\nint main()\n{\n int n,m;\n int a[105][105];\n scanf(\"%d%d\",&n,&m);\n for(int i=0;i<n;i++){\n for(int j=0;j<m;j++){\n scanf(\"%d\",&a[i][j]);\n }\n }\n for(int j=0;j<m;j++){\n int maxc = a[0][j];\n for(int i=1;i<n;i++){\n if(a[i][j]>maxc) maxc = a[i][j];\n }\n if(j>0) printf(\" \");\n printf(\"%d\",maxc);\n }\n printf(\"\\n\");\n return 0;\n}"
|
||
},
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{
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"code": "#include <bits/stdc++.h>\nusing namespace std;\nint arr[110][110];\nint main(){\n\tint n,m,num,cnt=0;\n\tcin>>n>>m; \n\tfor(int i=1; i<=n;i++){\n\t\tfor(int j=1; j<=m;j++){\n\t\tcin>>arr[i][j];\n\t\t}\n\t}\n\tfor(int i=1; i<=n;i++){\n\t\tfor(int j=1; j<=m;j++){\n\t\t\tcin>>num;\n\t\t\tif(num==arr[i][j]){\n\t\t\t\tcnt++;\n\t\t\t}\t\n\t\t}\n\tcout<<fixed<<setprecision(2)<<100.0*cnt/(n*m);\n\t}\n return 0;\n}"
|
||
}
|
||
]
|
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},
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{
|
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"tid": "tid1",
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"pid": 6604,
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},
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},
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{
|
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"seq": 4,
|
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|
||
}
|
||
]
|
||
},
|
||
{
|
||
"tid": "tid1",
|
||
"pid": 6605,
|
||
"title": "二维数组 - 判断题",
|
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{
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"score": 40,
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|
||
},
|
||
{
|
||
"seq": 2,
|
||
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|
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"score": 100,
|
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|
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|
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|
||
}
|
||
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|
||
}
|
||
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|
||
},
|
||
{
|
||
"uid": 413,
|
||
"name": "王佳琳",
|
||
"groups": [
|
||
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|
||
],
|
||
"stats": {
|
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|
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|
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|
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|
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"attemptCount": 0,
|
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"signals": [
|
||
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|
||
]
|
||
},
|
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"problems": []
|
||
}
|
||
],
|
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"objective": {
|
||
"6604": {
|
||
"title": "二维数组 - 选择题 - 题目详情 - 穹狼科创",
|
||
"questions": [
|
||
{
|
||
"no": 1,
|
||
"text": "【202606】小杨正在开发一款名为"星际网格"的游戏，他用二维数组 int map[5][4]; 来表示地图。已知 int 占 4 字节，如果 map 的内存地址是 0x2000 ，则表达式 &map + 1 的地址值是（ ）。",
|
||
"options": [
|
||
"0x204c",
|
||
"0x205c",
|
||
"0x2050",
|
||
"0x2058"
|
||
]
|
||
},
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||
{
|
||
"no": 2,
|
||
"text": "【202412】假定整型是 32 位，对一个 2 行 3 列的二维整数数组 array ，假设数组第一个元素在内存中的地址为 0x7ffee4065820 ，则第 2 行第 2 个元素的地址 &array[1][1] 为（ ）。 int array[2][3] = { {0, 1, 2}, {3, 4, 5} };",
|
||
"options": [
|
||
"0x7ffee4065824",
|
||
"0x7ffee4065828",
|
||
"0x7ffee406582c",
|
||
"0x7ffee4065830"
|
||
]
|
||
},
|
||
{
|
||
"no": 3,
|
||
"text": "【202503】下面（ ）正确定义了二维数组。",
|
||
"options": [
|
||
"int arr[3,4];",
|
||
"int arr[3][4];",
|
||
"int arr(3,4);",
|
||
"int a[3-4];"
|
||
]
|
||
},
|
||
{
|
||
"no": 4,
|
||
"text": "【202409】一个二维数组定义为 int arr[3][4]; （假设一个 int 变量占 4 个字节），则 int arr[0] 占用（ ）个字节的内存。",
|
||
"options": [
|
||
"3",
|
||
"4",
|
||
"12",
|
||
"16"
|
||
]
|
||
},
|
||
{
|
||
"no": 5,
|
||
"text": "【202506】下面的函数接收一个3行4列的二维数组并输出其中元素，则横线上不能填写（ ）。 void printArray(________) { for (int i = 0; i < 3; ++i) for (int j = 0; j < 4; ++j) std::cout << arr[i][j] << " "; }",
|
||
"options": [
|
||
"int arr[3][4]",
|
||
"int arr[][4]",
|
||
"int (*arr)[4]",
|
||
"int** arr"
|
||
]
|
||
}
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||
]
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||
},
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||
"6605": {
|
||
"title": "二维数组 - 判断题 - 题目详情 - 穹狼科创",
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||
"questions": [
|
||
{
|
||
"no": 1,
|
||
"text": "【202512】在 C++ 中，定义如下二维数组： int a[3][4]; ，数组 a 在内存中是按行优先连续存放的，即 a[0][0] 、 a[0][1] 、 a[0][2] 、 a[0][3] 在内存中是连续的。",
|
||
"options": [
|
||
"正确",
|
||
"错误"
|
||
]
|
||
},
|
||
{
|
||
"no": 2,
|
||
"text": "【202309】如果希望记录 10 个最长为 99 字节的字符串，可以将字符串数组定义为 char s[10][100]; 。",
|
||
"options": [
|
||
"正确",
|
||
"错误"
|
||
]
|
||
},
|
||
{
|
||
"no": 3,
|
||
"text": "【202503】二维数组作为函数参数时，必须显式指定所有维度的大小。",
|
||
"options": [
|
||
"正确",
|
||
"错误"
|
||
]
|
||
},
|
||
{
|
||
"no": 4,
|
||
"text": "【202412】 int arr[3][] 是一个正确的二维数组的声明。",
|
||
"options": [
|
||
"正确",
|
||
"错误"
|
||
]
|
||
},
|
||
{
|
||
"no": 5,
|
||
"text": "【202506】下面这段代码不合法，因为每一行都必须显式初始化3个元素。 int arr[2][3] = {{1, 2}, {3}};",
|
||
"options": [
|
||
"正确",
|
||
"错误"
|
||
]
|
||
}
|
||
]
|
||
}
|
||
}
|
||
} |